1.5.24: rxvt or console fail to shutdown due to ssh -f still running despite setsid()

[Michael Hoffman <b3i4old02 at sneakemail dot com>]

I originally reported this in October 2006 
<http://cygwin.com/ml/cygwin/2006-10/msg00399.html>:

[Michael Hoffman]
> > > When I log out of or shutdown my Windows login session, if I had a
> > > background process that I started within a Win32 rxvt session, I get an
> > > error that rxvt00000<some other hex numbers> has not shut down. For
> > > example if I use ssh -f or run ssh in the background using &, this
> > > symptom manifests.
> > >
> > > I can also see a related symptom if I am running using a Windows
> > > console. When I log out of bash, the console window will stick around
> > > until the ssh process is killed.
> > >
> > > I would like for these console windows and hidden rxvt windows to shut
> > > down without further confirmation. Is there a way to do this? Or a good
> > > workaround?
> > >
> > > I have Googled for this problem, and while I have found other related
> > > problems (such as ssh-agent continuing to run) I have not found any
> > > solutions for this case.

[Igor Peshansky]
> > "man nohup", "man setsid", in bash: "help disown".

[Michael Hoffman]
> Thanks, setsid works fine if I do not need to enter a password but 
> unfortunately will not work if I am using ssh -f to get an interactive 
> password before forking.
>
> Looking in the openssh source, I can see that ssh -f calls daemon(), 
> which should call setsid(). Is that correct? If so, why is it still 
> hanging onto the terminal?

I have just checked the source for the daemon() function and the setsid 
executable. They both call fork() and then setsid(). Do the console/rxvt 
process stick after calling ssh -f because file descriptors are left 
open? Can you suggest a strategy to deal with this?

Many thanks,
--
Michael Hoffman


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