Re: Why sh failed 'Process Substitution'?

["Daniel B." <dsb at smart dot net>]

Dave Korn wrote:
> Pan ruochen wrote:
> > Hi All,
> > Why sh failed to recognize Process Substitution, even if /bin/sh.exe
> > is a copy of /bin/bash.exe?
> > $cat test.sh
> > #!/bin/bash
> > A="A"
> > B="B"
> > diff <(echo $A) <(echo $B)
> > $sh test.sh
> > a.sh: line 4: syntax error near unexpected token `('
> > a.sh: line 4: `diff <(echo $A) <(echo $B)'
>
>   See the section "6.11 Bash POSIX Mode" in the bash info page, item 22:
>
> > " 22. Process substitution is not available. "

Pan,

What Dave didn't point out is that it's because you're running your
script using "sh test.sh" instead of using "test.sh" (or ./test.sh or
whatever, depending your execution search path setting (PATH)) (or even
using "bash test.sh").


Daniel






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