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RE: Bash v4.0 does not respect $PATH


As requested the output from perl -e "print $^X;"

Bash 3 => c:\opt\perl\bin\perl.exe

Bash 4 => /usr/bin/perl

As you would expect the program that is actually running.
But again Bash 4 is incorrectly getting /usr/bin/perl rather
than /opt/perl/bin/perl

-----Original Message-----
From: Csaba Raduly [mailto:rcsaba@gmail.com] 
Sent: 30 December 2009 08:52
To: cygwin@cygwin.com; Neil.Mowbray@calgacus.com
Subject: Re: Bash v4.0 does not respect $PATH

On Tue, Dec 29, 2009 at 11:21 PM,  Neil Mowbray wrote:
> Folks,
>
> I need associative arrays so I got the bash 4.0 source, compiled it 
> under cygwin and installed it in /usr/local/bin.
>
> I have ActiveState perl installed in /opt/perl which preceeds 
> /usr/local/bin:/bin:/usr/bin on my path. ?Using bash 4.0, 'which' says 
> I should get ActiveState perl, but actual execution gives cygwin perl 
> in /bin

Are you sure PATH is the same in bash 3 and 4? You only showed the PATH from
bash 4.
Just out of curiosity, what does

perl -e 'print $^X'

print in those two situations? Also, try running

for i in $(echo $PATH | sed -r -e "s/:/ /g"); do ls -l $i/perl; done

in both shells.


--
Life is complex, with real and imaginary parts


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