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[NEARLY SOLVED:] Re: make producing basename error that can't be captured by "make &> make.out"
- From: Paul Allen Newell <pnewell at cs dot cmu dot edu>
- To: cygwin at cygwin dot com
- Cc: pnewell at cs dot cmu dot edu
- Date: Thu, 01 Mar 2012 22:25:36 -0800
- Subject: [NEARLY SOLVED:] Re: make producing basename error that can't be captured by "make &> make.out"
- References: <4F5035D0.9070502@cs.cmu.edu> <4F506393.1030502@gmail.com>
On 3/1/2012 10:07 PM, Dave Korn wrote:
On 02/03/2012 02:52, Paul Allen Newell wrote:
[ weird problem symptoms ]
You probably have a script or shell alias getting in between you and the
real make. Please run "type make ; which -a make" in a bash shell and show us
the results.
cheers,
DaveK
Dave:
Thanks for the reply (smiled on the "weird problem symptoms" summation).
The result is:
+++
type make; which -a make
make is aliased to `settitle Making $(basename $PWD) && make "$@"'
/usr/bin/make
/usr/bin/make
+++
I groaned when I saw this as it is obvious the $(PWD) is feeding
basename and that's the "make" error. Thanks.
However, I am still trying to understand why this potentially incorrect
alias is creating text output to the screen which can't be redirected as
it isn't stdout or stderr ... or "3/4/5" as someone suggested I test.
Paul
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